1. (a) either (If in parallel) when one bulb fails, other
bulbs stay on
or (If in parallel) can
identify which bulb has failed; (1) 1
(b) (i) P = VI (1)
0.5 = 240 I
I = 2.1 × 10–3 A 1
s.f. in answer (–1) once only (1) 2
(ii) R
= V/I (1)
= 240/(2.1 × 10–3)
= 1.14 × 105 Ω or 1.15
× 105 Ω ans
accept (1.1 to 1.2) × 105 Ω. (1) 2
(iii) A
= ρ l / R (1)
= 1.1 × 10–6 × 6.0 ×
10–3 / (1.14 × 105)
(= 5.79 × 10–14 m2)
A = πr2 (1)
5.79 × 10–14 = πr2 so r = 1.4 × 10–7 m (1) 3
(iv) filament
too thin / fragile to be manufactured / used without damage;
allow ecf from (iii). (1) 1
4
[20]
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