1 (i) beam
current or intensity is reduced (1)
(because) fewer electrons are emitted (per sec) from the filament (1)
[or no beam as no electrons emitted if voltage of A
reduced enough (1)
(only)]
(ii) electrons travel faster [or more kinetic
energy] (1)
(because the force of) attraction to the anode is greater (1) 4
[7]
2
(a) KE
= 1.6 x 10-19 x 25 x
103;
(b) A calculation to include:
1.
K.E. = ½ x m x v2;
2. 4 x
10-15 = 0.5 x 9.1 x 10-31 x v2;
3. v
= 9.4 x 107 ms-1; 3
.
3 current = charge flow/
second or I = Q/t;
= 9.0 × 1015/s × 1.6 × 10 –19C;
= 1.4 × 10–3A; 3
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