Search This Blog

Tuesday, December 18, 2018

Tuesday, November 27, 2018

Resistivity

.         (a)     either   (If in parallel) when one bulb fails, other bulbs stay on
or        (If in parallel) can identify which bulb has failed; (1)                                1
  (b)   (i)      P = VI (1)
0.5 = 240 I
I = 2.1 × 10–3 A 1 s.f. in answer (–1) once only (1)                                      2
  (ii)   R = V/I (1)
= 240/(2.1 × 10–3)
= 1.14 × 105 Ω or 1.15 × 105 Ω ans
accept (1.1 to 1.2) × 10
5 Ω. (1)                                                                  2
  (iii)  A = ρ l / R (1)
= 1.1 × 10–6 × 6.0 × 10–3 / (1.14 × 105) (= 5.79 × 10–14 m2)
A = πr2 (1)
5.79 × 10–14 = πr2 so r = 1.4 × 10–7 m (1)                                                   3
  (iv)  filament too thin / fragile to be manufactured / used without damage;
allow ecf from (iii). (1)                                                                              1
 
         4
[20]

  2.     (a)     current µ p.d / voltage (for a metallic conductor)                                              M1
as long as temperature is constant / physical conditions remain constant             A1
(b)     (i)      (R =)  (= 0.0349)                                                                            B1
(ii)     R =           (Allow any subject  )                                                        C1
                                                      C1
resistivity = 5.6 ´ 10–5                                                                            A1
unit: ohm metre / W m            (Allow V m A–1)                                      A1
(5.6 ´ 10–n without unit or incorrect unit and n ¹ 5 or 3 – can score 2/4)
(5.6 ´ 10–3 W m – can score 3/4)
(5.6 ´ 10–3 W cm – can score 4/4)
[7]



Tuesday, October 16, 2018

Ohm's Law calculations



Ohm's Law


I ampere = I A
I milliamp = I mA           1/1000 A = 10-3A.
I microamp = I μA          = 1/1 000 000 A =10-6 A

I volt = I V
I kilovolt = I kV =1 000 V =103 V
I millivolt = I mV = 1/1000 V = 103 V

1 ohm = 1Ω
1 kilohm = 1KΩ =103
1 megohm        = 1 MΩ = 1 000 000 Ω = 106Ω





Find the potential difference needed to send a current of 2 μA through a resistor of 4 kΩ

                                    V=IR                 V = p.d. in V
I = current in A = 2μA = 2 x 10-6A
                                                     R =  resistance in Ω = 4kΩ = 4000Ω
                                    V          = 2 x 10-6 x 4000
= 8 X 10-3 V or 8 mV



1 Calculate the current through a resistor of 20 Ω if the potential difference across it is 0.5 V.

2 When a p.d. of 2 V is applied across a resistor the current is 0.1 A. Calculate the value of the resistor?

3 A p.d. of 100 V is applied across a resistor of 2 kΩ. Calculate the current?

4 Calculate the p.d. that will produce a current of 2 mA through a resistor of 4 kΩ?

5 Calculate the value of a resistor if a p.d. of 2 V produces a current of 0.5 μA.

6 Calculate the current through a 1.5 MΩ resistor when a p.d. of 4.5 V is applied.

7 A lamp operated by a 240 V supply takes a current of 0.625 A. Calculate the resistance of the lamp.

8 A coil of very fine copper wire is found to take a current of 0.75 A when a p.d. of 4.5 V is applied. If the wire has a resistance of 1.5 Ω per metre, Calculate length of wire in the coil?








Ohm's Law


I ampere = I A
I milliamp = I mA           1/1000 A = 10-3A.
I microamp = I μA          = 1/1 000 000 A =10-6 A

I volt = I V
I kilovolt = I kV =1 000 V =103 V
I millivolt = I mV = 1/1000 V = 103 V

1 ohm = 1Ω
1 kilohm = 1KΩ =103
1 megohm        = 1 MΩ = 1 000 000 Ω = 106Ω





Find the potential difference needed to send a current of 2 μA through a resistor of 4 kΩ

                                    V=IR                 V = p.d. in V
I = current in A = 2μA = 2 x 10-6A
                                                     R =  resistance in Ω = 4kΩ = 4000Ω
                                    V          = 2 x 10-6 x 4000
= 8 X 10-3 V or 8 mV



1 Calculate the current through a resistor of 20 Ω if the potential difference across it is 0.5 V.

2 When a p.d. of 2 V is applied across a resistor the current is 0.1 A. Calculate the value of the resistor?

3 A p.d. of 100 V is applied across a resistor of 2 kΩ. Calculate the current?

4 Calculate the p.d. that will produce a current of 2 mA through a resistor of 4 kΩ?

5 Calculate the value of a resistor if a p.d. of 2 V produces a current of 0.5 μA.

6 Calculate the current through a 1.5 MΩ resistor when a p.d. of 4.5 V is applied.

7 A lamp operated by a 240 V supply takes a current of 0.625 A. Calculate the resistance of the lamp.

8 A coil of very fine copper wire is found to take a current of 0.75 A when a p.d. of 4.5 V is applied. If the wire has a resistance of 1.5 Ω per metre, Calculate length of wire in the coil?


Wednesday, September 12, 2018

Circular motion Answers



Q=It


1.       36C
2.       500s
3.       12A
4.       66 weeks
5.       (i)190mA  (ii) 27 000 C